Expression of serum fibroblast growth factor 21 in patients with type 2 diabetes mellitus and nonalcoholic fatty liver disease and its relationship with liver fibrosis score / 中国综合临床
Using the methods of cross-sectional study, 422 patients with T2DM who attended to Cangzhou People's Hospital from December 2018 to January 2020, were selected and divided into T2DM group(121 cases) and T2DM with NAFLD group(301 cases) according to abdominal color ultrasound diagnosis.Serum FGF-21 level was detected by Enzyme-Linked Immuno Sorbent Assay(ELISA). Age-adjusted NFS was used to assess the risk of NAFLDliver fibrosis.Patients with T2DM and NAFLD were divided into the non NAFLDfibrosis group (NNF group, 125 cases ), the suspected NAFLDfibrosis group (SNF group, 136 cases)and the definited NAFLDfibrosis group (DNF group, 40 cases). A one-way analysis of variance or the Kruskal-Wallis H was used for comparison of continuous data between groups, and the chi-square test was used for comparison of categorical date between groups.Pearson method was used to analyze and compare the correlation of biochemical indexes in each group.Logistic regressions were used to explore related influencing factors.
Results:
Compared with the T2DM group, FGF-21 level was increased in T2DM with NAFLD group( P<0.05). The serum FGF-21 levels of NNF, SNF and DNF groups were significantly different ((297.03±52.71) ng/L, (321.52±69.42) ng/L, (274.08±30.82) ng/L; F=12.03, P<0.001). The level of FGF-21 in SNF group was higher than that in NNF group and DNF group, DNF group was lower than NNF group(all P<0.05). (2)Pearson correlation analysis showed NFS was negatively correlated with FGF-21( r=-0.162, P<0.01). (3)Logistic regressionsanalysis showed that the compensatory increase of FGF-21 level was the independent risk factor for NAFLD in T2DM patients ( OR 1.139, 95% CI 1.023-1.380, P<0.001). And the progressive decrease of FGF-21 level was the independent related factor of liver fibrosis in patients with T2DM combined with NAFLD ( OR 0.89, 95% CI 0.83-0.98, P=0.012).